Eighty percent of the students in a class (group A) share 40% of the candy equally. The remaining 20% of the students (group B) share the other 60% of the candy equally. The ratio of the amount of candy a student in group A has to the amount of candy a student in group B has is equal to what common fraction?

Question

Mathematics

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9 November, 13:17

Eighty percent of the students in a class (group A) share 40% of the candy equally. The remaining 20% of the students (group B) share the other 60% of the candy equally. The ratio of the amount of candy a student in group A has to the amount of candy a student in group B has is equal to what common fraction?

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Answers (2)

Know the Answer?

Norman · Answer 1

Answer:1/6

Bishop · Answer 2

1/6

Step-by-step explanation:

There is x candy in total and y students in total.

Group A consists of 0.8y students, and group B consists of 0.2y students.

Group A gets 40% of x, or 0.4x. Each student in group A gets 0.4x / (0.8y) = 0.5x/y candy per person.

Group B gets 60% of x, or 0.6x. Each student in group B gets 0.6x / (0.2y) = 3x/y candy per person.

The ratio of candy each student in group A has to the amount of candy each student in group B has is:

(0.5x/y) / (3x/y) = 0.5/3 = 1/6