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25 November, 10:39

Find three consecutive positive integers such that the product of the first and the third is 11 more than the second

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  1. 25 November, 13:49
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    3, 4, 5

    Step-by-step explanation:

    If the integers are x, x+1, and x+2, then:

    x (x+2) = x+1 + 11

    x² + 2x = x + 12

    x² + x - 12 = 0

    (x + 4) (x - 3) = 0

    x = - 4 or 3

    Since x is positive, x = 3. So the three integers are 3, 4, and 5.
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