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7 August, 07:15

What are the potential solutions to the equation below?

2ln (x+3) = 0

A. x=-3 and x--4

B. x=-2 and x-4

C. x = 2 and x = - 3

D. x = 2 and x = 4

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Answers (1)
  1. 7 August, 08:34
    0
    B - 2ln (1) = 0 and so x would have to be - 2 in order for that, and B is the only option with - 2
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