The function f (x) = xπ--√ gives the diameter, in inches, of a proposed spherical sculpture with a surface area of x square inches. The artist making the sculpture wants to know how the diameter changes if the surface area is increased. What is the average rate of change for the function as the surface area changes from 12.6 in. 2 to 28.3 in. 2? Round your answer to the nearest hundredth of an inch.

Question

Mathematics

Hamlet

3 March, 03:06

The function f (x) = xπ--√ gives the diameter, in inches, of a proposed spherical sculpture with a surface area of x square inches. The artist making the sculpture wants to know how the diameter changes if the surface area is increased. What is the average rate of change for the function as the surface area changes from 12.6 in. 2 to 28.3 in. 2? Round your answer to the nearest hundredth of an inch.

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Answers (1)

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Lacey Raymond · Answer 1

The average rate of change of f (x) = 3.14 inches⁻¹

The change in f (x) = 49.32 in

Step-by-step explanation:

The surface area of the spherical sculpture = x and its diameter f (x) = πx.

The average rate of change of f (x) as x changes is df (x) / dx = π = 3.14

Now the change in diameter Δf (x) = df (x) = (df (x) / dx) dx = πdx

dx = Δx = 28.3 in² - 12.6 in² = 15.7 in²

df (x) = π * 15.7 = 49.32 in