find 3 consecutive even integers such that the sum of the smaller 2 is 6 less than twice the largest one

n, n + 2, n + 4 - three consecutive even integers

n + 2 = 2 (n + 4) - 6 |use distributive property

n + 2 = (2) (n) + (2) (4) - 6

n + 2 = 2n + 8 - 6

n + 2 = 2n + 2 |subtract 2 from both sides

n = 2n |subtract 2n from both sides

-n = 0

n = 0

n + 2 = 0 + 2 = 2

n + 4 = 0 + 4 = 4

Answer: 0, 2, 4.