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19 October, 19:38

Find two consecutive even integers such that 3 times the smaller integer is 16 more than twice the larger

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  1. 19 October, 19:54
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    n, n + 2 - two consecutive even integers

    3n = 2 (n + 2) + 16 |use distributive property

    3n = (2) (n) + (2) (2) + 16

    3n = 2n + 4 + 16

    3n = 2n + 20 |subtract 2n from both sides

    n = 20

    n + 2 = 20 + 2 = 22

    Answer: 20, 22.
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