What is the vertex and axis of symmetry for y=4x^2-12x+9?

axis of symmetry x=3/2

vertex (3/2, 0)

Step-by-step explanation:

to find the axis of symmetry we use h = - b/2a

where ax^2 + bx+c

h = - (-12) / 2 (4)

h = 12/8

h = 3/2

the axis of symmetry is x = 3/2

the x coordinate of the vertex is h x=3/2

to find k, the y coordinate of the vertex, substitute x=3/2 into the equation

y=4x^2-12x+9

y=4 (3/2) ^2-12 (3/2) + 9

= 4 (9/4) - 6*3 + 9

= 9-18+9

= 0

the vertex (3/2, 0)