Factor completely

10x^2+2x-8

A.) 2 (5x-1) (x+4)

B.) 2 (5x-4) (x+1)

C.) 2 (5x+2) (x-2)

D.) 2 (5x-2) (x+2)

B.) 2 (5x-4) (x+1)

Step-by-step explanation:

10x^2+2x-8

= 2 (5x^2 + x - 4)

= 2 (5x^2 + 5x - 4x - 4)

= 2[5x (x + 1) - 4 (x + 1) ]

= 2 (5x-4) (x+1)

B.) 2 (5x - 4) (x + 1).

Step-by-step explanation:

10x^2+2x-8

First divide by the common factor 2:

= 2 (5x^2 + x - 4)

Now we factor the expression in the parentheses using the 'ac' method.

5 * - 4 = - 20 so to get the + x in the middle we need 5x - 4x:

= 2 (5x^2 + 5x - 4x - 4)

= 2[ 5x (x + 1) - 4 (x + 1) ]

= 2 (5x - 4) (x + 1) (answer).