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15 August, 19:26

Jennifer has a pocketful of change all in nickels and quarters. There are 11 coins with a total value of $1.15. Which system of equations can you use to find the number of each type of coin?

n + q = 11

n + q = 1.15

n + q = 11

5n+25q = 1.15

5n + 25q = 11

n + q = 1.15

n + q = 11

0.05n + 0.25q = 1.15

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Answers (1)
  1. 15 August, 20:50
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    n + q = 11

    0.05n + 0.25q = 1.15

    Step-by-step explanation:

    Hi, to answer this question we have to write a system of equations:

    n = number of nickel coins

    q = number of quarter coins

    Since there are 11 coins, the sum of the number of nickels and quarters must be 11:

    n+q = 11

    Since:

    1 nickel = $0.05

    1 quarter = $0.25

    The total value (1.15) must be equal to the product of the number of nickels (n) and the value of each nickel in dollars (0.05); plus the product of the number of quarters (q) and the value of each quarter in dollars (0.25)

    0.05n + 0.25q = 1.15

    The system is;

    n + q = 11

    0.05n + 0.25q = 1.15
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