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Mathematics
Natalia Andersen
12 December, 01:41
Factor trinomials; 2v^2 + 11v + 5
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Rambler
12 December, 02:55
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(V+5) (2v+1) is the answer
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Thomas Castaneda
12 December, 05:29
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(v + 5) (2v + 1)
Step-by-step explanation:
Given
2v² + 11v + 5
Consider the factors of the product of the coefficient of the v² term and the constant term which sum to give the coefficient of the v - term.
product = 2 * 5 = 10 and sum = + 11
The factors are + 10 and + 1
Use these factors to split the v - term
2v² + 10v + v + 5 (factor the first/second and third/fourth terms)
= 2v (v + 5) + 1 (v + 5) ← factor out (v + 5) from each term
= (v + 5) (2v + 1) ← in factored form
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