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17 July, 03:24

At the city museum, child admission is $6.10 and adult admission is $9.30. On Sunday, four times as many adult tickets as child tickets were sold, for a total sales of $909.30. How many child tickets were sold that day?

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  1. 17 July, 05:29
    0
    21 child tickets

    Step-by-step explanation:

    For this problem, you'd use a system of equations.

    First, define your variables.

    x = # of child tickets sold

    y = # of adult tickets sold

    There were 4 times as many adult tickets (y) as child tickets (x) sold, so:

    4 x = y

    4 x - y = 0

    93 (4 x - y = 0)

    372 x - 93 y = 0

    The total revenue was $909.30, adult tickets were $9.30 each, child tickets were $6.10 each, so:

    6.10 x + 9.30 y = 909.30

    10 (6.10 x + 9.30 y = 909.30)

    61 x + 93 y = 9093

    372 x - 93 y = 0

    433 x = 9093

    433 x / 433 = 9093 / 433

    x = 21
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