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18 November, 16:11

suppose the area of a square is x^2-10+25. What is the perimeter of the square? Hint * Find the length of the square first.

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  1. 18 November, 17:37
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    4x - 20

    Step-by-step explanation:

    The side length of the square is the square root of the area, so is ...

    s^2 = (x^2 - 10x + 25) = (x - 5) ^2

    s = (x - 5)

    Then the perimeter of the square is 4 times the side length:

    P = 4 (x - 5)

    P = 4x - 20
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