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12 February, 23:32

What is the solution for the following system of equations? Use ANY method to solve. 2x + 8y = 4 x = - 3y + 5 Question 4 options: x = 14, y = - 3 x = 2, y = - 3 x = - 3, y = - 3 x = 12, y = 5

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  1. 13 February, 00:27
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    x = 14, y = - 3

    Step-by-step explanation:

    Solve the following system:

    {2 x + 8 y = 4 | (equation 1)

    {x = 5 - 3 y | (equation 2)

    Express the system in standard form:

    {2 x + 8 y = 4 | (equation 1)

    {x + 3 y = 5 | (equation 2)

    Subtract 1/2 * (equation 1) from equation 2:

    {2 x + 8 y = 4 | (equation 1)

    {0 x - y = 3 | (equation 2)

    Divide equation 1 by 2:

    {x + 4 y = 2 | (equation 1)

    {0 x - y = 3 | (equation 2)

    Multiply equation 2 by - 1:

    {x + 4 y = 2 | (equation 1)

    {0 x+y = - 3 | (equation 2)

    Subtract 4 * (equation 2) from equation 1:

    {x+0 y = 14 | (equation 1)

    {0 x+y = - 3 | (equation 2)

    Collect results:

    Answer: x = 14, y = - 3
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