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18 October, 02:43

Write y = 2x^2 + 8x + 3 in vertex form.

y = 2 (x - 2) ^2 - 5

y = (x - 4) ^2 + 3

y = 2 (x + 2) ^2 - 5

y = (x + 4) ^2 + 3

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Answers (1)
  1. 18 October, 03:36
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    y = 2 (x + 2) ^2 - 5

    Step-by-step explanation:

    When y = ax^2 + bx + c is written in vertex form, it becomes ...

    y = a (x + b / (2a)) ^2 + (c - b^2 / (4a))

    The constant term in the squared binomial is b / (2a) = 8 / (2 (2)) = + 2. Only one answer choice matches:

    y = 2 (x + 2) ^2 - 5
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