3y^2-8y+4 factor each polynomial

(3x - 2) (x - 2)

Step-by-step explanation:

When factoring this, we know we will get something of the form (ax + b) (cx + d), which expands to ac (x^2) + (ad + bc) x + bd. Because ac = 3, and 3 is prime, a is 3 and c is 1, or vice versa. Knowing this, we have 3d + b = - 8 and bd = 4. Guess and check reveals b and d are - 2, and the answer is (3x - 2) (x - 2).

(3y-2) (y-2)

Step-by-step explanation:

3y^2 - 8y+4

We need to factor the polynomial

(3y) (y)

4 factors into 4*1 and 2*2

We need it to be negative since we have a negative 8

3*-2 - 2*1 = - 6-2 = - 8

-2*-2 = 4

So we have our factors

(3y-2) (y-2)