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7 November, 00:15

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122m, 22m and 120m. The advertisements yield an earning of rupees 5000 per m^2 per year. A company hired one of its walls for 3 months. How much rent did it pay?

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  1. 7 November, 01:16
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    1499750 rupees

    Step-by-step explanation:

    Let's find the area of the triangle first

    S = (122+20+120) / 2

    S = 131

    Area = √ (131 (131-122) (131-20) (131-120))

    Area=√ (131 (9) (111) (11))

    Area = √ (1439559)

    Area = 1199.8 m²

    5000 rupees per m² per year

    So in a year it will earn

    5000 = 1 m²

    1199.8m² = 5000*1199.8

    = 5999000 rupees for the year

    In three months it will earn

    5999000 * (3/12)

    = 5999000 (0.25)

    = 1499750 rupees
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