The sum of three consecutive numbers is 129 what is the smallest of the three numbers

Answer: n=42

Step-by-step explanation: Lets suppose n is a number. Since the numbers are consecutive, they would be:

n

n+1

n+2

If the sum is 129, then an equation would be

n+n+1+n+2=129

3n=126

n=42

So, the smallest number would be 42

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