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15 June, 14:54

Given: quadrilateral TALK is a parallelogram.

Prove: TA congruent LK and AL congruent KT

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  1. 15 June, 18:09
    0
    Proved by ASA congruence rule.

    Step-by-step explanation:

    Given the parallelogram TALK. We have to prove that TA is congruent to LK and AL is congruent to KT.

    ∵ TALK is a parallelogram,

    AL is parallel to segment TK and TA is parallel to KL and Line TL is a transversal.

    ⇒ ∠1 ≅ ∠ 4 and ∠2 ≅ ∠ 3

    In ΔTLK and ΔTLA

    ∠1 = ∠ 4 (∵Alternate angles)

    ∠2 = ∠ 3 (∵Alternate angles)

    TL=TL (∵Common)

    By ASA rule, ΔTLK ≅ ΔTLA

    ∴ By CPCT (Corresponding Parts of Congruent Triangles), TA ≅ LK and segment AL ≅ KT

    Hence Proved
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