Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 104 miles in the same time that Dana travels 96 miles. If Chuck's rate of travel is 4 mph more than Dana's, at what speed does Chuck travel?

Answer: Chuck's travel at a rate of 52mph

Step-by-step explanation:

For Chuck's trip:

D=RT

104 = (R+4) T

T = 104 / (R+4)

For Dana's trip:

96 = RT

T = 96/R

Set both equation for Chuck's and Dana together

104 / (R+4) = 96/R

Then we cross multiply

96 (R+4) = 104R

96R + 384 = 104R

104R - 96R = 384

8R = 384

To get R, divide both side by 8

8R/8 = 384/8

R = 48mph

This means Dana's speed is 48mph

Chuck's speed will be: 48mph+4mph = 52mph