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19 February, 10:52

Y=4x^3+3x^2-2x+9.

=> y'=?

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Answers (1)
  1. 19 February, 11:56
    0
    Step-by-step explanation:

    y'=dy/dx=d/dx (4x³+3x²-2x+9)

    = (3*4x^ (3-1) + 2*3x^ (2-1) - 2*1x^ (1-1) + 9*0

    y'=12x²+6x-2
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