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31 March, 10:31

What is the equation of a circle with center (-7, - 2) and radius 4?

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Answers (2)
  1. 31 March, 12:03
    0
    x2 + y2 + 14x + 4y - 37 = 0

    Step-by-step explanation:

    Equation of a circle in standard form can be written as,

    (x-h) 2 + (y-k) 2 = r2

    Here h, k are the coordinates of the centre and r is the radius as centre,

    (-7,-2) and r=4

    Substituting the values as given in the questions

    (x - (-7)) 2 + (y - (-2)) 2 = (4) 2

    Simplying it further,

    (x+7) 2 + (y+2) 2 = 16

    x2 + 14x + 49 + y2 + 4y + 4 = 16

    Equation required

    x2 + y2 + 14x + 4y - 37 = 0

    Therefore, the required equation of the circle.
  2. 31 March, 14:27
    0
    (x + 7) ² + (y + 2) ² = 16

    Step-by-step explanation:

    The equation of a circle in standard form is

    (x - h) ² + (y - k) ² = r²

    where (h, k) are the coordinates of the centre and r is the radius

    here (h, k) = ( - 7, - 2) and r = 4

    (x - ( - 7)) ² + (y - ( - 2)) ² = 4²

    (x + 7) ² + (y + 2) ² = 16 ← equation of circle
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