What is the equation of a circle with center (-7, - 2) and radius 4?

x2 + y2 + 14x + 4y - 37 = 0

Step-by-step explanation:

Equation of a circle in standard form can be written as,

(x-h) 2 + (y-k) 2 = r2

Here h, k are the coordinates of the centre and r is the radius as centre,

(-7,-2) and r=4

Substituting the values as given in the questions

(x - (-7)) 2 + (y - (-2)) 2 = (4) 2

Simplying it further,

(x+7) 2 + (y+2) 2 = 16

x2 + 14x + 49 + y2 + 4y + 4 = 16

Equation required

x2 + y2 + 14x + 4y - 37 = 0

Therefore, the required equation of the circle.

(x + 7) ² + (y + 2) ² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h) ² + (y - k) ² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = ( - 7, - 2) and r = 4

(x - ( - 7)) ² + (y - ( - 2)) ² = 4²

(x + 7) ² + (y + 2) ² = 16 ← equation of circle