A cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. A cylinder has a height of 20 centimeters and a diameter of 8 centimeters. What is the approximate volume of the tube? Round to the nearest whole cubic centimeter.

Question

Mathematics

Wall

5 May, 03:38

A cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. A cylinder has a height of 20 centimeters and a diameter of 8 centimeters. What is the approximate volume of the tube? Round to the nearest whole cubic centimeter.

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Answers (1)

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Lauren Galloway · Answer 1

1005.3 cm³

Step-by-step explanation:

Let's begin by listing out the given variables:

diameter (d) = 8 cm ⇒ r = 4 cm, height (h) = 20 cm

Formula for volume of cylinder is, πr²h

V = πr²h = π * 4² * 20 = 1,005.31 cm³

V ≈ 1005.3 cm³