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19 January, 16:29

A parabola has a vertex of (3,-2) and a y intercept of 7. what is the equation of this parabola

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  1. 19 January, 17:59
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    Step-by-step explanation:

    y=ax^2+bx+c

    when x=0, y=7 so c=7

    when x=3 then y=a*3^2+b*3+7=-2

    9a+3b+7=-2

    9a+3b=-2-7

    9a+3b=-9

    V (3,-2)

    3=-b/2a

    -b=3*2a

    b=-6a

    9a+3 * (-6a) = -9

    9a-18a=-9

    -9a=-9

    a=1

    b=-6*1

    b=-6a

    b=-6

    so y=x^2-6x+7
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