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4 November, 03:48

Shanice wants to make a 72% alcohol solution. She has already poured 2 L of pure water into a beaker. How many L of a 90% alcohol solution must she add to this to create the desired mixture?

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  1. 4 November, 06:46
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    8 Liters

    Step-by-step explanation:

    Percentage of Alcohol in water = 2L X 0 = 0

    Percentage of Alcohol to be added = xL X 0.9 = 0.9x

    New Volume = (x+2) Liters Desired Concentration = 0.72%

    Therefore:

    0+0.9x=0.72 (x+2)

    0.9x=0.72x+1.44

    Collect like terms

    0.9x-0.72x=1.44

    0.18x=1.44

    Divide both sides by 1.44

    x=8 Liters

    Therefore, Shanice must add 8 Liters of 90% alcohol solution to create the desired mixture
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