Consider the quadratic equation ax^2+bx+5=0, where a, b, and c are rational and the quadratic has two didstinct zeros if one zore is irrational, the other zero is

It can either be rational or irrational

Step-by-step explanation:

Given the quadratic equation ax²+bx+5 = 0, to get the zeros of the function, we will factorize the function to have;

ax²+bx = - 5

x (ax+b) = - 5

x = - 5 and ax+b = - 5

From the second function we have;

ax+b = - 5

ax = - 5-b

x = - 5-b/a

This shows that the other value of x can be rational or irrational depending on the values of a and b