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12 April, 08:33

The velocity of a car increases from 2.0 m/s to 16.0 m/s in a time period of 3.5 s. What was the average acceleration?

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  1. 12 April, 09:47
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    the acceleration is a=3ms^-2

    Step-by-step explanation:

    The distance is = 69.3m

    Apply the equation of motion

    v2=u2+2as

    the initial velocity is u=5ms-1

    The final velocity is v=21ms-1

    The acceleration is a=3ms-2

    The distance is

    s=v2-u22a

    =212-522⋅3

    =26*166
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