The velocity of a car increases from 2.0 m/s to 16.0 m/s in a time period of 3.5 s. What was the average acceleration?

the acceleration is a=3ms^-2

Step-by-step explanation:

The distance is = 69.3m

Apply the equation of motion

v2=u2+2as

the initial velocity is u=5ms-1

The final velocity is v=21ms-1

The acceleration is a=3ms-2

The distance is

s=v2-u22a

=212-522⋅3

=26*166