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22 May, 03:52

If f (x) = ax (x-3) and f (-2) = 5, what is the value of a?

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  1. 22 May, 05:40
    0
    a = 1/2

    Step-by-step explanation:

    f (x) = ax (x-3) and f (-2) = 5

    Replace x with - 2 and f (x) with 5

    5 = a (-2) (-2-3)

    5 = a (-2) (-5)

    5 = 10a

    Divide each side by 10

    5/10 = 10a/10

    1/2 = a
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