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7 May, 08:25

Given the cos theta is 12/13 and that the angle theta terminates in quadrant 4 l, then what is the value of sin theta

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  1. 7 May, 10:14
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    5/13

    Step-by-step explanation:

    R^2 = x^2 + y^2

    x is cosine

    y is sine

    r is the value in the denominator (here it is 13)

    Plug it in:

    13^2 = 12^2 + y^2

    169 = 144 + y^2

    Subtract 144 from both sides:

    169 - 144 = y^2

    25 = y^2

    Square root both sides:

    y = 5

    in other words, sin theta = 5/13
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