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25 October, 01:11

If x+y+z=0 Prove that (x^2+y^2+z^2) = 4 (xy+xz+yz) ^2

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  1. 25 October, 01:48
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    X + y + z = 0

    (x + y + z) ² = 0

    x² + y² + z² + 2xy + 2xz + 2yz = 0

    x² + y² + z² = - 2 (xy + xz + yz)

    (x² + y² + z²) ² = 4 (xy + xz + yz) ²

    eh, not same
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