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10 August, 16:58

According to a survey, 30% of US adults attend

church every Sunday. Suppose two adults from the

US are chosen at random. Let x represent the

number in this sample who attend church every

Sunday. Write the probability distribution of x.

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Answers (1)
  1. 10 August, 20:30
    0
    The probability distribution of x is given by

    P (x) = ⁿCₓ pˣ (1 - p) ⁿ⁻ˣ

    Where n is the number of trials, x is the variable of interest and p is the probability of success.

    P (x = 0) = 0.49

    P (x = 1) = 0.42

    P (x = 2) = 0.09

    Step-by-step explanation:

    The binomial distribution has the following features:

    • There are n repeated trials and are independent of each other.

    • There are only two possibilities: US adults attend church every Sunday or US adults do not attend church every Sunday

    • The probability of success does not change with trial to trial.

    Let x represent the number in this sample who attend church every

    Sunday, the probability distribution of x is given by

    P (x) = ⁿCₓ pˣ (1 - p) ⁿ⁻ˣ

    Where n is the number of trials, x is the variable of interest and p is the probability of success.

    For the given case

    Probability of success = p = 0.30

    Number of trials = n = 2

    Variable of interest = x = 0, 1, 2

    For P (x = 0):

    Here we have x = 0, n = 2 and p = 0.30

    P (x = 0) = ²C₀ (0.30⁰) (1 - 0.30) ²⁻⁰

    P (x = 0) = 0.49

    For P (x = 1):

    Here we have x = 1, n = 2 and p = 0.30

    P (x = 1) = ²C₁ (0.30¹) (1 - 0.30) ²⁻¹

    P (x = 1) = 0.42

    For P (x = 2):

    Here we have x = 2, n = 2 and p = 0.30

    P (x = 2) = ²C₂ (0.30²) (1 - 0.30) ²⁻²

    P (x = 2) = 0.09
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