Four equivalent forms of a quadratic function are given. Which form displays the y-intercept of the function?

f (x) = 3 (x2 + 2x - 48)

f (x) = 3 (x + 1) 2 - 147

f (x) = 3x2 + 6x - 144

f (x) = 3 (X + 8) (x-6)

Question

Mathematics

Jace Gibson

23 December, 17:15

Four equivalent forms of a quadratic function are given. Which form displays the y-intercept of the function?

f (x) = 3 (x2 + 2x - 48)

f (x) = 3 (x + 1) 2 - 147

f (x) = 3x2 + 6x - 144

f (x) = 3 (X + 8) (x-6)

+3

Answers (1)

Know the Answer?

Raymond · Answer 1

f (x) = 3x2 + 6x - 144

Step-by-step explanation:

The y intercept is the value of the function when x = 0

We want the easiest way to see when x=0

We want a constant term after all multiplication is done. The constant term is the y intercept

f (x) = 3x2 + 6x - 144 has a constant term

Four equivalent forms of a quadratic function are given. Which form displays the y-intercept of the function?f (x) = 3 (x2 + 2x - 48)f (x) = 3 (x + 1) 2 - 147f (x) = 3x2 + 6x - 144f (x) = 3 (X + 8) (x-6)

Four equivalent forms of a quadratic function are given. Which form displays the y-intercept of the function?

f (x) = 3 (x2 + 2x - 48)

f (x) = 3 (x + 1) 2 - 147

f (x) = 3x2 + 6x - 144

f (x) = 3 (X + 8) (x-6)