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19 March, 02:48

A circular above ground pool has a height of 52 inches, and a volume of 1100 ft^3. What is the radius of the pool to the nearest tenth of a foot? Use the equation V=pi*r^2*h.

(V = volume, r = radius, and h=height)

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Answers (2)
  1. 19 March, 04:10
    0
    9.0 ft

    Step-by-step explanation:

    Height = 52/12 ft = 13/3 ft

    1100 = 3.14 * r² * 13/3

    r² = 80.84272415

    r = 8.991258208
  2. 19 March, 05:47
    0
    9 ft

    Step-by-step explanation:

    The pool is in the shape of a cylinder

    V = pi r^2h

    We need to change the height from inches to ft

    52 inches * 1ft/12 inches = 13/3 ft

    1100 = pi * r^2 * 13/3

    Multiply each side by 3

    3300 = pi * r^2 * 13/3 * 3

    3300 = pi * r^2 * 13

    Divide each side by 13pi

    3300/13pi = pi * r^2 * 13/13pi

    3300 / (13*3.14) = r^2

    80.84272415 = r^2

    Take the square root of each side

    sqrt (80.84272415) = sqrt (r^2)

    8.991258208 = r

    To the nearest foot

    9 = r
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