Three consecutive integers have a sum of 78. find the inte

Let the 3 numbers be x, x+1, x+2

Given sum of those 3 consecutive integers are 78

X+x+1+x+2=78

3x+3=78

3 (x+1) = 78

X+1=26

X=26-1

X=25

Therefore the numbers are 25,26,27

Answer: 25, 26, and 27

Step-by-step explanation: Three consecutive integers can be represented as followed. Let's use "T" as our variable.

T → first integer

T + 1 → second integer

T + 2 → third integer

Since the sum of our three consecutive integers is 78, our equation will be as followed.

T + T + 1 + T + 2 = 78

We can simplify on the left.

3t + 3 = 78

-3 - 3 ← subtract 3 on both sides

3t = 75

:3 : 3 ← divide by 3 on both sides

T = 25

T + 1 = 26

T + 2 = 27

Therefore, our three consecutive integers are 25, 26, and 27.