If the value of b decreases, but the value of m remains the same, what will happen to the x-intercept?

A) The x-intercept decreases.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

Consider the function f (x) = mx + b, where m > 0.

If the value of b decreases, but the value of m remains the same, what will happen to the x-intercept?

A) The x-intercept decreases.

B) The x-intercept increases.

C) The x-intercept approaches zero.

D) The x-intercept remains the same

Here is my answer:

Given the function f (x) = mx + b, where m > 0.

x-intercept happen when y = 0

When b decreases and m stay the same, the value of f (x) will be decreased. For example: f (x) = 2x + 3 = 0

When b unchanged, m unchanged we have: 2x + 3 = 0 x = - 3/2

When b decreases to 2, m unchanged we have: 2x + 2 = 0 x = - 1

Obviously that, - 1 < - 3/2 so the x-intercept will be decreased