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16 July, 10:34

If sinx = sqrt (3) / 2, and 90° < x < 180°, what is cos (x/2) ?

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  1. 16 July, 12:01
    0
    cos 60° = 1/2

    Step-by-step explanation:

    * Lets explain how to solve the question

    - If angle Ф lies in the first quadrant then sin Ф, cos Ф and tan Ф

    are positive values

    - The equivalent angle of angle Ф in the second quadrant is 180° - Ф

    and sin Ф is positive but cos Ф and tan Ф are negative

    - The equivalent angle of angle Ф in the third quadrant is 180° + Ф

    and tan Ф is positive but cos Ф and sin Ф are negative

    - The equivalent angle of angle Ф in the fourth quadrant is 360° - Ф

    and cos Ф is positive but sin Ф and tan Ф are negative

    * Lets solve the problem

    ∵ sin x = √3/2

    ∵ 90° < x < 180°

    ∴ ∠ x lies in the second quadrant

    ∴ m∠ x = 180° - Ф

    - Let sin Ф = √3/2

    ∴ Ф = sin^-1 (√3/2)

    ∴ Ф = 60°

    ∵ x = 180° - Ф

    ∴ x = 180° - 60°

    ∴ x = 120°

    - To find cos (x/2) divide 120° by 2

    ∵ cos (120°/2) = cos (60°)

    ∴ cos 60° = 1/2
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