Suppose a city with population 600,000 has been growing at a rate of 6% per year. If this rate continues, find the population of this city in 13 years.

The population will be approximately 1279757

Step-by-step explanation:

This problem consists of a exponential growth. The formula to find the value of a exponencial growth is:

P = Po*r^t

where P is the population after t years, Po is the inicial population, and r is the rate that the population grows.

In this case, Po = 600000, t = 13, r = 1.06

So, calculating the population after 13 years, we have:

P = 600000 * 1.06^13 = 1279756.956

So the population will be approximately 1279757

The population would be 1,068,000

Step-by-step explanation:

In this question, we are asked to calculate the population of a city which has a growth rate of 6% per year in the next 13 years.

We proceed as follows.

Since the percentage of growth is 6% per year, in the next 13 years, the total expected percentage of would be 6 * 13 = 78%

This means in the next 13 years, the city is expected to have a population growth that is 78% more than what it has at present.

Now, we translate this into a value as follows.

78% of the initial population

From the question, the initial population is 600,000

78/100 * 600,000 = 468,000

Now the population of the city at the 13th year would be 600,000 + 468,000 = 1,068,000