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24 February, 17:03

rewrite 2x^2+2y^2-8x+10y+2=0 in standard form. Find the center and radius of the circle. Show all of your work for full credit

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  1. 24 February, 19:34
    0
    Radius of circle is 12.64 units and

    center of circle is (8,-10).

    Step-by-step explanation:

    Given,

    Equation of circle is 2x^2+2y^2-8x+10y+3=0.

    comparing given equation ofvcircle with the general ewuation of circle x^2+y^2+2gx+2fy+C=0 we get,

    g=-8

    f=10

    and, c=2

    Now we know,

    center of circle = (-g,-f)

    ={ - (-8), - (10) }

    = (8,-10)

    Again, radius of circle is given by:

    r = (g^2+f^2-c^2) ^1/2

    ={ (-8) ^2 + (10) ^2 - (2) ^2}^1/2

    = (64+100-4) ^1/2

    = (160) ^1/2

    =root under 160

    =12.64 units

    [note i use root as () ^1/2 cause i couldnt fint root sign in my mobile]
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