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21 January, 23:02

Who much time would it take for a train accelerating at 21.5 m/s2 to go from

13.2 m/s to 38.9 m/s?

+2
Answers (2)
  1. 22 January, 01:42
    0
    To find the time taken, we use the equation:

    v

    =Then to find the time taken, we use the equation:

    v = u + at

    where:

    v is the final velocity of the train

    u is the initial velocity of the train

    a is the train's acceleration

    t is the time taken

    So, we get:

    t = (v-u) / a

    t = (38.9 - 13.2) / 21.5

    t = 25.7/21.5

    t = 1.19 seconds
  2. 22 January, 02:47
    0
    Step-by-step explanation:

    v=u+at

    38.9=13.2+21.5 t

    21.5 t=38.9-13.2

    21.5 t=25.7

    t=25.7/21.5≈1.195 s
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