One afternoon the water park sold 525 tickets for a total of $13,545. Child tickets cost $19 each, and adult tickets cost $40 each. How many of each kind of ticket were sold?

You need to set up 2 problems for this. Let's start with the # of tickets sold & variables.

c = # of child tickets sold

a = # of adult tickets sold

c + a = 525

Now we need to set up the equation for the money.

c = # of child tickets sold

a = # of adult tickets sold

19c + 40a = 13,545

Now put the two equations by each other.

c + a = 525

19c + 40a = 13,545

Now I will solve for one of the variables.

c + a = 525

-a - a

c = 525 - a

Now I plug it into the other equation.

19 (525) + 40a = 13,545

Solve.

9,975 + 40a = 13,545

-9,975

40a = 3,570 / 40

a = 89.25

89 rounded?

then plug in a on the second equation

c + 89 = 525

-89 - 89

c = 436

so the answer is:

Sold 89 adult tickets.

Sold 436 kids tickets.

Answer: The no of child and adult are 355 and 170 respectively

Step-by-step explanation:

Let the no of tickets for child be x

and the no of tickets for adult be y

Given x+y=525 ... [1]

19x+40y=13545 ... [2]

Multiplying [1] by 19

19x+19y=9975 ... [3]

Subtracting [3] from [2]

19x+40y-19x - 19y = 13545-9975

21y=3570

Dividing both sides by 21

y=170

Putting value of y in [1]

x+170=525

Subtracting 170 both sides

x+170-170 = 525-170

x=355

No of child = 355

No of adults = 170