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9 January, 21:15

A ball is thrown straight up with an initial velocity of 35.7 m/s. How long does

it take to hit the ground?

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Answers (1)
  1. 9 January, 22:04
    0
    y = v₀t - gt²/2

    For y=0 (back to where we started),

    0 = t (v₀ - gt/2)

    t=0 (which we knew) or v₀ - gt/2 = 0

    v₀ = gt/2

    2v₀ = gt

    t = 2v₀/g

    t = 2 (35.7 m/s) / (9.8 m/s/s) = 7.3 seconds

    Answer: 7.3 seconds
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