Which polynomial function has a root of 3 with multiplicity 2 and roots of - 10 and - 1 with multiplicity 1? f (x) = (x - 10) (x - 1) (x + 3) (x + 3) f (x) = x (x - 10) (x - 1) (x + 3) f (x) = (x + 10) (x + 1) (x - 3) (x - 3) f (x) = x (x + 10) (x + 1) (x - 3) (x - 3)

Question

Mathematics

Paige Chang

22 October, 00:01

Which polynomial function has a root of 3 with multiplicity 2 and roots of - 10 and - 1 with multiplicity 1? f (x) = (x - 10) (x - 1) (x + 3) (x + 3) f (x) = x (x - 10) (x - 1) (x + 3) f (x) = (x + 10) (x + 1) (x - 3) (x - 3) f (x) = x (x + 10) (x + 1) (x - 3) (x - 3)

+2

Answers (1)

Know the Answer?

Leyla · Answer 1

(x+10) (x+1) (x-3) (x-3)

Step-by-step explanation:

root of 3 with multiplicity 2

(x-3) ^2 or (x-3) (x-3)

root of - 10

(x - - 10) is (x+10)

root of - 1

(x - - 1) is (x+1)

(x-3) ^2 (x+10) (x+1)