Ask Question
8 November, 00:37

Suppose a parabola has a vertex in quadrant IV and a<0 in the equation y=ax^2+bx+c. how many real solutions will the equation ax^2+bx+c=0 have?

+3
Answers (1)
  1. 8 November, 03:08
    0
    Given the vertex is in quadrat IV, it is below the y-axis.

    Given a < 0, the parabola open downdards.

    Those two facts together implies that the parabola does not touch the y-axis, meaning y is never 0, and the equation ax^2 + bx + c = 0 does not have any real solutions.

    Answer; None
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Suppose a parabola has a vertex in quadrant IV and a ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers