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14 May, 05:17

what process could you use to determine the zeros, x-intercepts, or solutions of a polynomial Y=9x^2+12x+4

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  1. 14 May, 08:21
    0
    Step-by-step explanation:

    Y=9x²+12x+4

    Y=9 (x² + (12/9) x+4/9)

    Y=9 (x² + (4/3) x+4/9)

    Y=9 (x²+2 (2/3) x+4/9)

    Y=9 (x²+2 (2/3) x+4/9)

    Y=9 (x+2/3) ²

    Y = 0 : x+2/3 = 0

    x = - 2/3 is the solution of a polynomial
  2. 14 May, 08:55
    0
    Y=4 + (64rza r=r z = r a=r
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