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Yesterday, 20:13

the members of the boosters organization at your high school bought new balls for the school. they spent $22.00 per basketball and $30.00 per football, spending a total of $648.00. They bought 6 more footballs than basketballs. How many of each type of ball did they buy?

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  1. Yesterday, 21:47
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    9 basket balls, 15 foot balls

    Step-by-step explanation:

    Let x be the number of basket ball

    y be the number of foot ball

    1 basket ball = $22

    so x basket ball = 22x

    1 foot ball = $30

    so y foot ball = 30y

    Total cost = 648

    The equation becomes 22x + 30y = 648

    Given : They bought 6 more footballs than basketballs.

    foot ball (y) = 6 more basket balls (x)

    so y = x + 6

    we solve for x and y

    Now we plug in x+6 for y in the equation 22x + 30y = 648

    22x + 30 (x+6) = 648

    22x + 30x + 180 = 648

    Subtract 180 on both sides

    52x = 468

    Divide both sides by 52

    so x = 9

    Number of basket ball x = 9

    Number of foot ball y=x+6 = 9 + 6 = 15
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