What is the equation of the line that passes through (4, - 1) and (-2, 3) ?

2x - 3y - 5 = 0

2x + 3y - 5 = 0

-2x + 3y - 5 = 0

2x + 3y - 5 = 0

Step-by-step explanation:

hello:

(4; -1) : x=4 and y = - 1 so : 2 (4) + 3 (-1) - 5 = 0 means : 8-3-5 = 0 ... true

(-2; 3) : x=-2 and y = 3 so : 2 (-2) + 3 (3) - 5 = 0 means : - 4+9-5 = 0 ... true

2x+3y-5=0

Step-by-step explanation:

m = (y2-y1) / (x2-x1)

m = (3 - (-1)) / (-2-4)

m = (3+1) / -6

m=4/-6

simplify

m=-2/3

y-y1=m (x-x1)

y - (-1) = -2/3 (x-4)

y+1=-2/3x+8/3

y=-2/3x+8/3-1

y=-2/3x+8/3-3/3

y=-2/3x+5/3

y - (-2/3x) = 5/3

y+2/3x=5/3

3 (y+2/3x) = 3 (5/3)

3y+6/3x=15/3

3y+2x=5

2x+3y=5

2x+3y-5=0