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6 February, 21:46

Suppose that the price p (in dollars) and the weekly sales x (in thousands of units) of a certain commodity satisfy the demand equation 8p cubedplusx squaredequals104 comma 000. Determine the rate at which sales are changing at a time when xequals200 , pequals20 , and the price is falling at the rate of $.50 per week.

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  1. 6 February, 22:15
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    dx/dt = 12 (in thousands of units / week)

    Step-by-step explanation:

    We have from problem statement that:

    8*p³ + x² = 104 (1)

    Where p is price in $, and "x" is the weekly sales in thousands of units

    All variables x and p change in relation to time then

    Differentiating on both sides of the equation, we get:

    24*p²*dp/dt + 2*x*dx/dt = 0 (1)

    We need to find dx/dt and we know

    p = 20

    x = 200

    And price is falling at the rate of 0,5 $/week

    Then plugging these values in equation (1)

    24*p²*dp/dt = - 2*x*dx/dt

    24 * (20) ² (-0,5) = - 400*dx/dt

    -4800 = - 400*dx/dt

    dx/dt = 4800/400

    dx/dt = 12 (in thousands of units / week)
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