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10 January, 02:02

What algebraic expression must be subtracted from the sum of y2 + 5y - 1 and 3y2-2y + 4 to give 2y2 + 7y-2 as the result

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  1. 10 January, 04:21
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    The required expression is 2y² - 4y + 5.

    Step-by-step explanation:

    We have to find the sum of first 2 expressions and then subtracting an expression, let us consider a, to give the third expression. We have to find a.

    y² + 5y - 1 + 3y² - 2y + 4

    We have to group the like terms and doing the addition as,

    = y² + 3y² + 5y - 2y - 1 + 4

    = 4y² + 3y + 3

    Now we have to subtract an expression a from the above sum to get the third expression.

    4y² + 3y + 3 - a = 2y² + 7y - 2

    Now we have to group the terms as,

    a = 4y² + 3y + 3 - (2y² + 7y - 2)

    = 4y² + 3y + 3 - 2y² - 7y + 2

    Rearranging the terms as,

    a = 4y² - 2y² + 3y - 7y + 3 + 2

    = 2y² - 4y + 5

    So the required expression is 2y² - 4y + 5.
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