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1 September, 16:08

Let X be a sum of results when rolling die twice. P (X at most 5) =

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  1. 1 September, 18:22
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    Answer:The probability of sum of results when rolling dice twice giving at most 5, P (X) = 5 / 18

    Step-by-step explanation:

    A dice has 6 outcomes, S = [1, 2, 3, 4, 5, 6}

    When two dice are rolled, the no of outcomes n (S) = 6 * 6 = 36

    S = { (1, 1), (1, 2) ... (1, 6)

    (2, 1) ... (2, 6)

    ... (6,6) }

    Le X be the event that sum of two dice when rolled is at most 5

    At most refers to lesser than or equal to,

    Therefore the outcomes for event X = { (1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1) }

    n (X) = 10

    P (X) = n (X) / n (S)

    = 10 / 36 = 5 / 18
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