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3 March, 22:30

If 2 (a^2+b^2) = (a+b) ^2 then,

>a+b=0,

>ab=0,

>a=b,

>2a=b

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Answers (1)
  1. 4 March, 01:27
    0
    2· (a^2 + b^2) = (a + b) ^2

    2·a^2 + 2·b^2 = a^2 + 2·a·b + b^2

    a^2 + b^2 = 2·a·b

    a^2 - 2·a·b + b^2 = 0

    (a - b) ^2 = 0

    a = b
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