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5 October, 02:08

What is the vertex if the function f (x) = -x^2-2x-1

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  1. 5 October, 03:33
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    Vertex = (-1,0)

    x^2-2x-1

    y = - (x + 1) ^2 + 0

    Use the vertex form, y=a (x-h) ^2+k, to determine the values of a, h, and k.

    Find the vertex (h, k) = (-1,0)
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